ALL QUESTIONS (12)
MATRICES
1) If A= 1 3 & B= 1 -1
0 1 0 1
with relation AX = B, then find X
2) A= 1 2 3 B= 1 0 2 C= 4 4 10
-1 -3 2 3 4 5 4 2 14
with the relation 2A+ kB = C, then find k.
3) If A= 4 2
1 1 find (A- 2I)(A - 3I), where I is a unit matrix.
4) Solve:
a) 5x -12y = -9; 7x - 6y = -8.
b) 2x + 3y - 4z = 1, 3x -y +2z = -2, 5x -9y +14z =3.
c) x -2y +3z = 6, x + 4y + z = 12, x -3y + 2z =1.
d) x -2y - 3z = 4, 2x +y -3z = 5, -x +y +2z =3.
e)
5) Construct a 3x4 matrix whose elements are aᵢⱼ= i + j.
6) If x+ y y - z = 3 -1
z -2x y- x 1 1 then find x, y, z
7) If A= 3 1
7 5, find Matrix x and y so that A²+ xI = yA. Hence find A⁻¹.
8) If A= 1 & B= 3 1 -2
5
7
Verify (AB)'= B'A'.
9) Find the inverse of a b
c d given that ad - bc ≠ 0.
10) If A= 1 1
0 1 show that A³= 1 3
0 1
11) Find A= 1 1 2 B= 1 2
2 1 0 2 0
-1 1
Verify B'A' = (AB)'.
12) If A= x² B= x C= -2
y² 2y 9 with the relation A - 3B= C then find x and y.
13) If A= 1 x 1 B= 1 3 2 & C= 1
2 5 1 2
15 3 2 x with the relation ABC= 0, then find x.
14) Find the inverse of
A= -1 1 2
3 -1 1
-1 3 4
15) Find the adjoint of the matrix
A= 1 0 -1
3 4 5
0 -6 -7 and hence find the inverse matrix.
16) If A= 2 3
5 -2 then show that A⁻¹= A/19
17) A= x² B= 2x C= 7
y² 3y -3 with the relation A+ 2B = 3C, then find x and y.
18) Construct a matrix of order 3x2 whose element in iᵗʰ row and jᵗʰ column is given by aᵢⱼ = (3i+ j)/2.
19) If A= x² 3 4 B= -3x 1 -5 C= 4 4 -1
1 9 8 -3 -2 -6 -2 7 2 with the relation A+ B = C find the value of x.
20) Let a be a square matrix, show that (1/2) (A+ A') is symmetric matrix and that (1/2)(A- A') is a skew symmetric matrix. Hence show that every square matrix may be expressed as the sum of symmetric and skew symmetric matrices.
21) If x+ y= 7 0 & x -y= 3 0
2 5 0 3 then find Matrix x and y.
22) If 2x+ 3y=2 3 & 3x +2y=-2 2
4 0 1 -5 then find Matrix x and y.
23) If A= 1 -1 B= 2 1
2 3 1 0 then show (A+ B)²≠ A²+ 2AB+ B²
24) If A= 3 -2
4 -2 with the relation A²= kA - 2I, I is the unit matrix, then find k
25) If A= x y B= -2 0 C= 1 2
-1 5 -1 5 0 0 with the relation 2A = B - C, then find x and y.
26) If (x y z) -(-5 3 0)= (-5 6 7), determine x, y, z.
27) If A= 2 -3 B= a b C= -3 4
4 0 c d 5 -1 determine a, b, c, d.
28) Express in a single matrix
A= 1 3 B= 8 4
1 -4 4 8 as relation 4A - (1/2) B
29) If A= 1 2 3 B= 1 0 0
0 1 2 0 0 0
0 0 1 0 0 1 with the relation -2(X + A)= 3X + B, then find Matrix X.
30) If A= 3 5
-4 2 find A²- 5A - 14I, then find inverse of A
31) A men invests Rs50000 into two types of bonds . The first bond pays 5% interest per year and the second bond pays 6% intrest per year. Use matrix multiplication to determine how to divide Rs50000 among two types of bonds so as to obtain an annual total interest of Rs2780.
DETERMINANTS
1) x² y² z²
x³ y³ z³
xyz yzx zxy = xyz(x - y)(y- z)(z - x)(xy + yz+ zx).
2) y+ z x+ y x
z+ x y+ z y =(x³+ y³+z³- 3xyz)
x+y z+x z
3) a b- c c - b
a- c b c- a
a- b b - a c = (a+ b- c)(b+ c - a)(c +a - b)
4) (b + c)² a² a²
b² (c+ a)² b²
c² c² (a+ b)²= 2abc(a+ b+ c)³
5) y+ z z y
z z+ x x = 4xyz
y x x+ y
6) x x² 1+ x³
y y² 1+ y³ = 0
z z² 1+ z³
Then show that xyz= -1.
7) x+ a b c
c x+ b a = 0
a b x+ c
Then x is. 0, -(a+b+c)
8) b²c² bc b+c
c²a² ca c+a = 0
a²b² ab a+ b
9) 1 1 1
a² b² c²
a³ b³ c³= (a - b)(b- c)(c- a)(ab+ bc+ ca).
10) 2- x 3 3
3 4- x 5 = 0
3 5 4- x
Then find the roots of the equation. 0,-1,11
11) 2 0 0 1
-6 -4 0 2
-5 -1 -4 2
-3 2 6 -3
Evaluate. 188
12) -a² ab ac
ba -b² bc= 4a²b²c²
ac bc -c²
13) If s= a+ b+ c, then find the value of
s+ c a b
c s+ a b
c a s+b. 2s³
14) 1+ a 1 1
1 1+ b 1
1 1 1+c
= abc(1+ 1/a + 1/b + 1/c)
15) a b c
a² b² c²
bc ca ab
= (a- b)(b- c)(c - a)(ab + bc+ ca).
16) a b c
a- b b- c c- a
b+c c+ a a+ b = a³+ b³+ c³- 3abc
17) a - b - c 2a 2a
2b b-c-a 2b =(a+b+c)³
2c 2c c-a-b
18) x³ x² x
y³ y² y
z³ z² z
= xyz(x - y)(y - z)(x - z).
19) a²+1 ab ac
ba b²+1 bc= a²+ b²+c²+1
ca cb c²+1
20) 1 378 1893
1 372 1892= 1
1 371 1891
21) b+c c+a a+b 2a 2b 2c
q+r r+p p+q= 2p 2q 2r
y+z z+x x+y 2x 2y 2z
22) 1 a a²- bc
1 b b²-ac= 0
1 c c²-ab
23) 42 6 1
28 4 7 = 0
14 2 3
24) c- a a- b b- c
a- b b- c c- a= 0
b-c c- a a-
25) 219 198 181
240 225 198 = 0
265 240 219
26) x+ 2 1 -3
1 x-3 x-2= 0
-3 -2 1
Then find x. 2, 12
21) a b- c c- b
a- c b c-a
a- b b- a c
= (a+ b- c)(b+ c-a)(c+ a- b).
22) b²+ c² a² a²
b² c²+ a² b²
c² c² a²+ b²
= a² bc ac + c²
a²+ ab b² ac
ab b²+bc c²
23) 1 a bc 1 1 1
1 b ca a b c
1 c ab a² b² c²
24) x² x 1
0 2 1 = 28
3. 1 4
Then find x. 3,-17/7
25) b 1 a
c -1 1 = 1+ a²+ b²+ c²
1 -b -ct
25) 3+ x 5 2
1 7+x 6= 0
2 5 3+ x
Then find x. 0,-1,-12
26) 1 1 1
a b c
a³ b³ c³ express in factors. (a- b)(b- c)(c -a)(a+ b+ c)
27) b+ c a a
b c+ a b. = 4abc
c c a+ b
28) x -6 -1
2 -3x x -3 = 0
-3 2x x+2
Find x. 1,2,-3
29) Find the area of triangle with Vertices (-1,-8)(3,2)(-2,-3). 15
30) A triangle with Vertices (x,4); (2,-6); (5,4) have area= 35 sq. cm. Find the value of x. -2,12
31) Find the possible values of K if the system of equations x+ ky- z= 0, Kx - y -z = 0, x+ y- z= 0 has a non zero solution. 1
32)
5) Solve: x+ y= 2; 2x - z=1; 2y- 3z =1. 3/4,5/4,1/2
) 2x-y-z=-6; x+3y-z= 0; 2x+ y+z=-2. -2,1,1
) x - y=1; x+ z= -6; x+ y- 2z = 3. -2,-3,-4
)
6) Find the value of K
3 - K -1 1
- K 5 - K -1 = 0
1 -1 3- K 2,3,6
7) Determine whether the following system are consistent or dependent.
a) 2x- y+z=2; 3x+ 2y- 4z =1; x - 4y+6z=3. dependent
b) x+ 3y- 2z=2; 3x -y- z=1; 2x+ 6y-4z = 3. Inconsistent
c) x - y+3z =6; x+ 3y- 3z =-4; 5x + 3y+3z =10. Consistent
d) Given the following system of equations is consistent: (x - a)(y- b)= ab; (x -b)(y- c)= bc; (x - c)(y- a)= ac. Prove a= b = c.
e)
8) If the system of equations is consistent. Find the value of k.
a) 2x+ 3y-8= 0; 7x- 5y+3= 0; 4x - 6y+ k= 0. 8
INVERSE TRIGONOMETRICAL FUNCTION
1) Show that: 4 tan⁻¹(1/5) - tan⁻¹(1/70) + tan⁻¹(1/99) = π/4.
2) Solve: tan⁻¹(2+ x) + tan⁻¹(2- x) = tan⁻¹(2/3). ±3
3) Show that sinn⁻¹{x/√(1+ x²)} + cos⁻¹{(x+1)/√(x²+ 2x +2)}= tan⁻¹(x²+ x+1).
4) Prove: cot(π/4 - 2 cot⁻¹3)= 7.
5) Find x if sin⁻¹(5/x) + sin⁻¹(12/x) =π/2. ±13
6) Find the value of sin cot⁻¹ cos(tan⁻¹x). √{(1+ x²)/(2+ x²)}
7) Solve: sin⁻¹6x + sin⁻¹(6 √3 x) =-π/2. ±1/12
8) Solve: sin⁻¹{2a/(1+ a²)} + sin⁻¹{2b/(1+ b²)} = 2 tan⁻¹x. (a+ b)/(1- ab)
9) Solve: sin(cos⁻¹cot(2tan⁻¹x))= 0. ±1, √(3± 2√2)
10) Prove: sin⁻¹(√3/2) + 2tan⁻¹(1/√3) = 2π/3.
11) Show that: sin⁻¹(1/√17) + cos⁻¹(9/√85) = tan⁻¹(1/2).
12) Find the value of cos(2 cos⁻¹x + sin⁻¹x) at x= 1/5. -2√6/5
13) Solve: cos(sin⁻¹x) = 1/9. ±4√5/9
14) Show: tan⁻¹(1/3) + tan⁻¹(1/5) + tan⁻¹(1/7) + tan⁻¹(1/8) =π/4.
15) Solve: tan⁻¹2x + tan⁻¹3x =π/4. 1/6
16) Show: tan⁻¹{(1/2) tan2A}+ tan⁻¹(cotA) + tan⁻¹(cot³A) = 0.
17) Show: 2(tan⁻¹1+ tan⁻¹(1/2) + tan⁻¹(1/3))=π.
18) Show that: tan⁻¹x + cot⁻¹(x +1) = tan⁻¹(x²+ x+1).
19) Prove: 2 cos⁻¹x = cos⁻¹(2x²-1).
20) Prove: tan⁻¹(1/4) + tan⁻¹(2/9) = (1/2) cos⁻¹(3/5).
21) Evaluate: tan(2tan⁻¹(1/5) - π/4). -7/17
22) (1/2) tan⁻¹x = cos⁻¹[{1+ √(1+ x²)}/2√(1+ x²)].
23) If tan⁻¹a + tan⁻¹b + tan⁻¹c=π, then show that a+ b+ c= abc.
24) Show: sin⁻¹(4/5) + cos⁻¹(2/√5) = cot⁻¹(2/11).
25) Evaluate:
a) tan(1/2) (cos⁻¹(√5/3)). (1/2) (3- √5)
b) cos(cos⁻¹(-√3/2) +π/6). -1
c) sin[π/3 - sin⁻¹(-1/2)]. 1
26) If tan⁻¹x + tan⁻¹y + tan⁻¹z =π/2, show that xy+yz+zx= 1.
27) Show that sec²(tan⁻¹2) + cosec²(cot⁻¹3) =15.
28) Show: sin⁻¹(12/13) + cos⁻¹(4/5) + tan⁻¹(63/16) =π.
29) If cos⁻¹(x/2) + cos⁻¹(y/3) = J, show that 9x²- 12xy cosK+ 4y²= 36 sin²K.
30) Show:
a) tan⁻¹[{√(1+ x²)+ √(1- x²)}/{√(1+ x²) - √(1- x²)]=π/4 + (1/2) cos⁻¹x².
b) cos⁻¹(4/5) + cot⁻¹(5/3) = tan⁻¹(27/11).
c) tan(2tan⁻¹a)= 2tan(tan⁻¹a + tan⁻¹a³).
d) cot⁻¹{(pq +1)/(p - q)} + cot⁻¹{(qr +1)/(q - r)} + cot⁻¹{(rp +1)/(r - p)} = 0.
e) sin[sin⁻¹(1/2) + cos⁻¹(3/5)]= (3+4√3)/10.
f) cos[tan⁻¹(15/8) - sin⁻¹(7/25)]= 297/425.
31) Solve the following:
a) tan⁻¹{1/(2x+1)} + tan⁻¹{1/(4x+1)}) = tan⁻¹(2/x²). 0, -2/3, 3
b) tan⁻¹(x+1) + cospt⁻¹(x-1) = sin⁻¹(4/5) + cot⁻¹(3/4). ±4√(3/7)
c) tan⁻¹(x -1) + tan⁻¹x + tan⁻¹(x +1) = tan⁻¹(3x). 0, ±1/2
d) sin⁻¹x + sin⁻¹2x=π/3. 1/6
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